upgrading grounds
#5
there will be no voltage increase...
there will be no current increase (thats measurable)
period... electronics theory dictates this it's the way the electrons work...
what it will do is stop the wires from acting as a fuse and burning out should you draw too much current...
there will be no current increase (thats measurable)
period... electronics theory dictates this it's the way the electrons work...
what it will do is stop the wires from acting as a fuse and burning out should you draw too much current...
#8
Originally posted by gatherer
there will be no voltage increase...
there will be no current increase (thats measurable)
period... electronics theory dictates this it's the way the electrons work...
what it will do is stop the wires from acting as a fuse and burning out should you draw too much current...
there will be no voltage increase...
there will be no current increase (thats measurable)
period... electronics theory dictates this it's the way the electrons work...
what it will do is stop the wires from acting as a fuse and burning out should you draw too much current...
at idle... not likely
but when the amps under full load if you have a small 16 awg wire there, there is going to be voltage drop at the amp
dont belive me, look it up
#9
Originally posted by loudsubz
your right jay, no current drop thats measureable, but there will be voltage drop
at idle... not likely
but when the amps under full load if you have a small 16 awg wire there, there is going to be voltage drop at the amp
dont belive me, look it up
your right jay, no current drop thats measureable, but there will be voltage drop
at idle... not likely
but when the amps under full load if you have a small 16 awg wire there, there is going to be voltage drop at the amp
dont belive me, look it up
V=IxR
is if the voltage changes one of the 2 other factors are changing most likely current... under full load amps ussually demand (depends on size and power rating of amp) more current then 16 gauge can provide... so whats happening? well the wire is heating up for one... wither the wiring heating up the resistance goes up ... and higher resistance less current ... and with the change in the current and resistance of the whole system the voltage drops... it's all related and easy to explain....
remember I have 4 diplomas in electronics and computers... hell I have a 3 month class on ohm's law....
#10
Originally posted by gatherer
V=IxR
is if the voltage changes one of the 2 other factors are changing most likely current... under full load amps ussually demand (depends on size and power rating of amp) more current then 16 gauge can provide... so whats happening? well the wire is heating up for one... wither the wiring heating up the resistance goes up ... and higher resistance less current ... and with the change in the current and resistance of the whole system the voltage drops... it's all related and easy to explain....
remember I have 4 diplomas in electronics and computers... hell I have a 3 month class on ohm's law....
V=IxR
is if the voltage changes one of the 2 other factors are changing most likely current... under full load amps ussually demand (depends on size and power rating of amp) more current then 16 gauge can provide... so whats happening? well the wire is heating up for one... wither the wiring heating up the resistance goes up ... and higher resistance less current ... and with the change in the current and resistance of the whole system the voltage drops... it's all related and easy to explain....
remember I have 4 diplomas in electronics and computers... hell I have a 3 month class on ohm's law....
but your basically saying what I said
#13
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