upgrading grounds
:confused:
i was told that if i upgrade my grounds (i.e. the gound from the battery terminal to the chassis) it would increase the voltage going to my amp. Is this true? (upgrade to 0 guage wire) ???? |
yes it will but not by much
it helps flow more electrons |
do u know if there be any voltage increase? (i.e 05v?)
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doubtful there'd be any significant increase..
0?? shyt, i'd say 2 maximum is all you'd need..and if it was me i'd replace all my grounds anyway.. |
there will be no voltage increase...
there will be no current increase (thats measurable) period... electronics theory dictates this it's the way the electrons work... what it will do is stop the wires from acting as a fuse and burning out should you draw too much current... |
Upgrade the wire from the alt positive to the battery positive, battery negative to chassis and alt to chassis all with the same wire you have running to your system.
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thanks for all the input guys, very helpful
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Originally posted by gatherer there will be no voltage increase... there will be no current increase (thats measurable) period... electronics theory dictates this it's the way the electrons work... what it will do is stop the wires from acting as a fuse and burning out should you draw too much current... at idle... not likely but when the amps under full load if you have a small 16 awg wire there, there is going to be voltage drop at the amp dont belive me, look it up |
Originally posted by loudsubz your right jay, no current drop thats measureable, but there will be voltage drop at idle... not likely but when the amps under full load if you have a small 16 awg wire there, there is going to be voltage drop at the amp dont belive me, look it up V=IxR is if the voltage changes one of the 2 other factors are changing most likely current... under full load amps ussually demand (depends on size and power rating of amp) more current then 16 gauge can provide... so whats happening? well the wire is heating up for one... wither the wiring heating up the resistance goes up ... and higher resistance less current ... and with the change in the current and resistance of the whole system the voltage drops... it's all related and easy to explain.... remember I have 4 diplomas in electronics and computers... hell I have a 3 month class on ohm's law.... :rolleyes: |
Originally posted by gatherer V=IxR is if the voltage changes one of the 2 other factors are changing most likely current... under full load amps ussually demand (depends on size and power rating of amp) more current then 16 gauge can provide... so whats happening? well the wire is heating up for one... wither the wiring heating up the resistance goes up ... and higher resistance less current ... and with the change in the current and resistance of the whole system the voltage drops... it's all related and easy to explain.... remember I have 4 diplomas in electronics and computers... hell I have a 3 month class on ohm's law.... :rolleyes: but your basically saying what I said :p |
Originally posted by loudsubz thats all and good but your basically saying what I said :p I remember ohm's law. :D Fun stuff. |
i double checked it, gatherer is right. good work guys!
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good ol grade 11
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