Math questions
12-May-2003, 09:12 PM
#23
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Originally posted by gatherer
yeah thanks cosmic I owe you a coffee for that ...
do you also have the one that is for 1=2 (it's with trig not calculus)
yeah thanks cosmic I owe you a coffee for that ...
do you also have the one that is for 1=2 (it's with trig not calculus)
1=2 ... nope... don't have that one sorry
12-May-2003, 09:15 PM
#24
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I personally am not a fan in math. 
When it comes to math, i'm an idiot. Dont get me wrong but I can add numbers and ****, but....
What will you need to know all that stuff for? (honestly, dont flame, im asking)
:hourglass
When it comes to math, i'm an idiot. Dont get me wrong but I can add numbers and ****, but....
What will you need to know all that stuff for? (honestly, dont flame, im asking)
:hourglass
12-May-2003, 09:16 PM
#25
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Location: on a race track
Posts: 17,846
must have been an RCC school special ... I'll have to raid the offices again looking for it ... ohhh well
but hey thanks for the 1=0 ... with that it can be proven that every number equals zero
so since we know from cosmic's proof that 1 = 0 we can multiply both sides by 2 to get 2 = 0 and sine 2=0 = 1 we can then state 1=2 ...
yeah I'm soooo bored at work .. someone call in and complain about fast busies when making calls or LD recordings or something ...
but hey thanks for the 1=0 ... with that it can be proven that every number equals zero
so since we know from cosmic's proof that 1 = 0 we can multiply both sides by 2 to get 2 = 0 and sine 2=0 = 1 we can then state 1=2 ...
yeah I'm soooo bored at work .. someone call in and complain about fast busies when making calls or LD recordings or something ...
12-May-2003, 09:30 PM
#28
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ya i guess you could be right, it just depends what you want to do, in my case, i dont think I will need those crazy equations.
I want to take Business Administration and Entrepreneurial Studies in Uni/Col
I want to take Business Administration and Entrepreneurial Studies in Uni/Col
12-May-2003, 10:53 PM
#33
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Join Date: Jul 2002
Location: sauga
Posts: 1,313
Originally posted by 2 rice 4 u
I know i'm going to need some math, but not too much crazy equations to find out an angle of a triangle or the CosA shiznat !
I know i'm going to need some math, but not too much crazy equations to find out an angle of a triangle or the CosA shiznat !
that's really just simple calculus, and to get into business in university you need calculus, and will have to take atleast one year of math in university
13-May-2003, 08:18 AM
#36
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3 - ( 2 a + 4 – 3 ) + 3a + 3 ( 2 a- 3 + 6 ) = 3 + (4a + 6) + 15
3-2a-4+3+3a+6a-9+18 = 3+4a+6+15
group all like terms on each side together
11+7a = 24+4a
group the "a" terms on one side, the others on the other side. when you move from one side to the other, you must change the "sign" -positive or negative- in front of each number.
7a-4a = 24-11
3a=13
divide both sides by 3
a= 13/3
3-2a-4+3+3a+6a-9+18 = 3+4a+6+15
group all like terms on each side together
11+7a = 24+4a
group the "a" terms on one side, the others on the other side. when you move from one side to the other, you must change the "sign" -positive or negative- in front of each number.
7a-4a = 24-11
3a=13
divide both sides by 3
a= 13/3
13-May-2003, 09:19 AM
#40
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Location: Etobicoke
Posts: 3,662
Originally posted by cosmic
Int(f(x)*g(x))dx = f(x)*G(x) - Int(f'(x)*G(x))dx
with G(x): the primitive function of g(x)
and f'(x): the derivative of f(x)
Now watch the following 'proof':
Int(1/x^2 * 2x)dx = 1/x^2 * x^2 - Int(-2/x^3 * x^2)dx
{just take f(x) = 1/x^2 and g(x) = 2x}
this yields:
Int(2/x)dx = 1 - Int(-2/x)dx = 1 + Int(2/x)dx
substracting Int(2/x)dx on both sides yields:
0 = 1
math is your friend
Int(f(x)*g(x))dx = f(x)*G(x) - Int(f'(x)*G(x))dx
with G(x): the primitive function of g(x)
and f'(x): the derivative of f(x)
Now watch the following 'proof':
Int(1/x^2 * 2x)dx = 1/x^2 * x^2 - Int(-2/x^3 * x^2)dx
{just take f(x) = 1/x^2 and g(x) = 2x}
this yields:
Int(2/x)dx = 1 - Int(-2/x)dx = 1 + Int(2/x)dx
substracting Int(2/x)dx on both sides yields:
0 = 1
math is your friend
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