math help a.s.a.p
14-Oct-2002, 10:22 PM
#2
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Location: Vancouver
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y = x^2 +2x +3
to locate a quadratic equation's vertex, simply use the following equation:
x=-b/2a
thus, a = 1, b = 2 , c = 3
x= -2/2
x= -1
so, to find point y
y=(-1)^2 + 2(-1) + 3
y=2
the vertex is at (-1,2)
since a > 0, then this function opens up, thus, the point is a minimum.
Ans:
A minimum at -1,2
to locate a quadratic equation's vertex, simply use the following equation:
x=-b/2a
thus, a = 1, b = 2 , c = 3
x= -2/2
x= -1
so, to find point y
y=(-1)^2 + 2(-1) + 3
y=2
the vertex is at (-1,2)
since a > 0, then this function opens up, thus, the point is a minimum.
Ans:
A minimum at -1,2
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